Dallas Cowboys quarterback Dak Prescott insisted that he wants to remain with the team for the long haul, despite offseason contract drama.
Cowboys quarterback Dak Prescott expressed confidence in his agent’s ability to get a long-term deal done with Dallas, explaining that he hopes to spend his entire career with the organization despite rumors that the two sides are still far apart on a potential deal.
Per USA Today, guaranteed money and the length of a potential extension have both been major roadblocks in negotiations, with Prescott standing firm in his demands for larger guarantees and a four-year deal rather than a five-year deal.
However, his Wednesday comments paint a different picture, and fans should be cautiously optimistic about the fifth-year signal caller’s apparent desire to remain in Dallas.
Dak wants to be a Cowboy long-term, so what’s the hold-up?
While Prescott’s true value has been hotly debated, Jerry Jones and the Dallas front office likely have no choice but to cave into some of his demands. With Patrick Mahomes signing a record-breaking contract extension in the offseason, the price of a franchise quarterback is only going up.
Although Prescott has admittedly underperformed with talented rosters, he boasts a 40-24 record as Dallas’s starter and has brought the team to the playoffs twice in four seasons. With the Cowboys fielding one of their most talented teams in recent years and debuting new head coach Mike McCarthy in 2020, hesitation on the front office’s part could make him demand even more.
The quarterback is saying all of the right things at the moment, but it’s no secret that negotiations have been intense. The two sides appear dug in, and spurning Prescott at this point could leave Dallas with a playoff-ready roster and no franchise quarterback, a definitively undesirable position.
If Dallas does not get serious about locking up its quarterback soon, Prescott could face the same franchise tag drama that Kirk Cousins did in Washington, forcing the Cowboys to either pay up or look elsewhere.